Solution for Section 3.4 Question 2

2.  Here A = 95.

f = 95 div 50 = 1
B = 95 mod 50 = 45
t = 45 div 20 = 2
C = 45 mod 20 = 5
n = 5 div 10 = 0
D = 5 mod 10 = 5
v = 5 div 5 = 1

f = 1, t = 2, n = 0, v = 1, so one 50¢ coin, two 20¢ coins and one 5¢ coin would give you 95¢ .

Back to Section 3.4