Solution for Section 4.1.4

Solution for Section 4.1 Question 4

4.

	1	+	1	+	1	+	......	+	1	=
	1 · 2		2 · 3		3 · 4				n · (n + 1)

n

1

i · (i + 1)

S

i = 1

Back to Section 4.1