Hint for Section 4.2 Question 2b
2b)
Let P(n) be the claim: |
n |
|
= |
|
for all integers n 1. |
S |
j = 1 |
P(1) is the statement: |
1 |
|
= |
|
|
S |
j = 1 |
|
P(k) is the statement: |
k |
|
= |
|
|
S |
i = 1 |
|
P(k+1) is the statement: |
k + 1 |
|
= |
|
|
S |
i = 1 |
For a proof by induction, you first need to check that the statement P(1) is true. Then
assume that P(k) is true and use this to show that P(k + 1) is true.
The statement P(1) is true since |
1 |
|
= |
|
|
S |
i = 1 |
Now assume that the statement P(k) is true. We now need to show that the left-hand side
of P(k+1) is equal to the right-hand side of P(k+1).
L.H.S of P(k+1) |
= |
k + 1 |
|
S |
i = 1 |
|
|
|
|
= |
k |
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+ |
|
S |
i = 1 |
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|
|
Use your assumption that the statement P(k) is true to simplify this expression. Your
goal is to end up with the right-hand side of P(k+1).
Back to Section 4.2
Full solution