Solution for Section 6.1 Question 3b

3b) Since 61 is larger than half the number of integers in the original list, there will be only two possible places in which to split the list to obtain a sublist of 61 consecutive integers.

The first way is to cut the list such that from -52 to where you have cut the list will give 61 consecutive integers. Let x be the integer after which you will cut the list. Then  x - (-52) + 1 = 61, and so x = 8. You could cut the list between the integers 8 and 9.

The other way is to have 61 consecutive integers from the spot you cut the list to the final integer, 57.  Let x be the integer before which you will cut the list.
Then 57 - x + 1 = 61, so x = -3. You could cut the list between the integers -4 and -3. 

Back to Section 6.1