Hint for Section 3.10 Question 2

2. We know from the previous section that gcd(105, 56) = 7, and that m = 2 and n = -4 is one solution to the linear Diophantine equation
  105m + 56n = -14.

Let m₀ = 2, n₀ = -4, a = 105, b = 56 and d = 7, and apply Theorem 3.10.1.

Back to Section 3.10
Full solution