Solution for Section G.1 Question 1

1. The set {0,1} with the binary operation multiplication does not form a group.

The closure property is satisfied since 0*0 = 0, 0*1 = 1*0 = 0 and 1*1 = 1.
The associative property is satisfied (since multiplication is associative).
The element 1 is the identity since 1*a = a = a*1 for each value a in the set {0,1}.
But the element 0 has no inverse. There is no element a such that 0*a = 1 (the identity).

Back to Section G.1